24x^2-72x-96=0

Solution for 24x^2-72x-96=0 equation:

24x^2-72x-96=0

a = 24; b = -72; c = -96;
Δ = b2-4ac
Δ = -722-4·24·(-96)
Δ = 14400
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{14400}=120$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-72)-120}{2*24}=\frac{-48}{48}
=-1
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-72)+120}{2*24}=\frac{192}{48}
=4
$